Code AnalysisHard 50s
Trace: Timing-Safe Compare
Why is this comparison vulnerable?
Starter code
function check(a, b) {
if (a.length !== b.length) return false;
for (let i = 0; i < a.length; i++) if (a[i] !== b[i]) return false;
return true;
}Think you can answer under pressure?
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