Multiple ChoiceIntermediate 45s
Stateless lambda to function pointer
When can a lambda be converted to a plain function pointer?
Options
- 1Always, regardless of captures, because the closure type converts to a pointer through an implicit conversion.
- 2When it has no captures (an empty closure), so it can decay to a pointer to its static call operator.
- 3Never; a lambda can never become a plain function pointer and must always be wrapped in std::function.
- 4Only if the lambda is declared mutable, since a mutable operator() has the required function-pointer layout.
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